4TH

LARGEST NUMBER

4TH
Apr 2nd, 2026
2
0
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JavaScript 2.83 KB | Source Code | 0 0
  1. function findlargest(num1, num2, num3)
  2. {
  3. if (num1 > num2 && num1 > num3)
  4. {
  5. console.log("num1 is largest.");
  6. }
  7. else if (num2 > num1 && num2 > num3)
  8. {
  9. console.log("num2 is largest.");
  10. }
  11. else
  12. {
  13. console.log("num3 is largest.");
  14. }
  15. }
  16. const num1 = 70;
  17. const num2 = 90;
  18. const num3 = 100;
  19. findlargest(num1, num2, num3);
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